python密码错误3次不能再输入
Python实现账号密码输错三次即锁定功能简单示例本文实例讲述了Python实现账号密码输错三次即锁定功能。分享给大家供大家参考,具体如下:
初学Python—1
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#实现账号输错三次即锁定 user = "hubery" passwd = "123" confirm = 0 lock = 0 fileOpen = open ( "username.txt" , "a+" ) fileOpen.seek( 0 ) for i in range ( 3 ): username = input ( "username:" ) passsword = input ( "password:" ) for line in fileOpen.readlines(): if username = = line.strip(): print ( "账户已经锁定!" ) lock = 1 break else : continue fileOpen.seek( 0 ) if user = = username and lock = = 0 : if passwd = = passsword: print ( "欢迎,欢迎!" ) confirm = 1 break else : print ( "账号户或者密码错误!" ) continue elif lock = = 1 : continue else : print ( "1账号或者密码错误!" ) continue fileOpen.close() if confirm = = 0 and lock = = 0 : fileWrite = open ( "username.txt" , "a" ) fileWrite.write(username + "\n" ) fileWrite.close() |
基本功能可以实现;
锁定的账号为第三次输错的用户名(待完善)
以下为完善版本,如有错误,请告知
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import os user = "hubery" passwd = "123" count = 0 lock = 0 fileOpen = open ( "username.txt" , "a+" ) fileOpen.seek( 0 ) while 1 : for i in range ( 5 ): username = input ( "username:" ) passsword = input ( "password:" ) for line in fileOpen.readlines(): if username = = line.strip(): print ( "账户已经锁定!" ) lock = 1 break else : continue fileOpen.seek( 0 ) if user = = username: if lock = = 1 : continue elif passsword = = passwd: print ( "欢迎,欢迎!" ) os._exit( 0 ) elif count < 2 : print ( "账号或者密码错误!" ) count + = 1 continue else : fileOpen.write(username + "\n" ) fileOpen.flush() print ( "密码输入错误超过三次,账户已经锁定!" ) fileOpen.seek( 0 ) continue else : print ( "账号密码错误!" ) continue check = input ( "还想验证其他账户?(yes-继续,no-退出)" ) if "no" = = check.lower(): os._exit( 0 ) else : continue fileOpen.close() |
希望本文所述对大家Python程序设计有所帮助。
原文链接:https://blog.csdn.net/sen1013293436/article/details/64545220