php中怎么分割数组
PHP实现数组根据某个字段进行水平合并，横向合并案例分析本文实例讲述了PHP实现数组根据某个字段进行水平合并，横向合并。分享给大家供大家参考，具体如下：
PHP数组水平合并，横向合并，两条数据合并成一行
需求
将两个素组中日期相同的合并成一行
数组a
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Array( [0] => Array ( [date] => 2019-04-02 [today_pay_money] => 168.00 [today_pay_num] => 1 [yesterday_pay_money] => 999.00 [yesterday_pay_num] => 1 ) [1] => Array ( [date] => 2019-04-09 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 0.00 [yesterday_pay_num] => 0 ) [2] => Array ( [date] => 2019-05-05 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 2.00 [yesterday_pay_num] => 1 ) [3] => Array ( [date] => 2019-05-11 [today_pay_money] => 0.00 [today_pay_num] => 0 [yesterday_pay_money] => [yesterday_pay_num] => 1 )) |
数组B
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Array( [0] => Array ( [date] => 2019-05-07 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 0 [yesterday_pay_num1] => 0 ) [1] => Array ( [date] => 2019-05-11 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 1 [yesterday_pay_num1] => 1 )) |
需要格式
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Array( [2019-04-02] => Array ( [date] => 2019-04-02 [today_pay_money] => 168.00 [today_pay_num] => 1 [yesterday_pay_money] => 999.00 [yesterday_pay_num] => 1 ) [2019-04-09] => Array ( [date] => 2019-04-09 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 0.00 [yesterday_pay_num] => 0 ) [2019-05-05] => Array ( [date] => 2019-05-05 [today_pay_money] => 0.01 [today_pay_num] => 1 [yesterday_pay_money] => 2.00 [yesterday_pay_num] => 1 ) [2019-05-11] => Array ( [date] => 2019-05-11 [today_pay_money] => 0.00 [today_pay_num] => 0 [yesterday_pay_money] => [yesterday_pay_num] => 1 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 1 [yesterday_pay_num1] => 1 ) [2019-05-07] => Array ( [date] => 2019-05-07 [today_pay_money1] => 0 [today_pay_num1] => 0 [yesterday_pay_money1] => 0 [yesterday_pay_num1] => 0 )) |
代码实现
先将a,b数组合并，判断当前日期下是否空，空的话直接赋值，不空的话，将已有素组和当前数组合并
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$total = array_merge($a,$b));$res = array();foreach ($total as $k => $v) { if (empty($res[$v['date']])) $res[$v['date']] = $v; else $res[$v['date']]= array_merge($res[$v['date']],$v);} |
希望本文所述对大家PHP程序设计有所帮助。
原文链接：https://blog.csdn.net/flysnownet/article/details/90111860