有个朋友说能不能用函数来实现对身份证的校验，所以这里用Oracle的函数来实现，其他数据库异曲同工..
身份证校验函数
CREATE OR REPLACE FUNCTION Func_checkidcard (p_idcard IN VARCHAR2) RETURN INT
IS
v_regstr VARCHAR2 (2000);
v_sum NUMBER;
v_mod NUMBER;
v_checkcode CHAR (11) := '10X98765432';
v_checkbit CHAR (1);
v_areacode VARCHAR2 (2000) := '11,12,13,14,15,21,22,23,31,32,33,34,35,36,37,41,42,43,44,45,46,50,51,52,53,54,61,62,63,64,65,71,81,82,91,';
BEGIN
CASE LENGTHB (p_idcard)
WHEN 15
THEN -- 15位
IF INSTRB (v_areacode, SUBSTR (p_idcard, 1, 2) || ',') = 0 THEN
RETURN 0;
END IF;
IF MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 2)) 1900, 400) = 0
OR
(
MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 2)) 1900, 100) <> 0
AND
MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 2)) 1900, 4) = 0
)
THEN -- 闰年
v_regstr :=
'^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}$';
ELSE
v_regstr :=
'^[1-9][0-9]{5}[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}$';
END IF;
IF REGEXP_LIKE (p_idcard, v_regstr) THEN
RETURN 1;
ELSE
RETURN 0;
END IF;
WHEN 18
THEN -- 18位
IF INSTRB (v_areacode, SUBSTRB (p_idcard, 1, 2) || ',') = 0 THEN
RETURN 0;
END IF;
IF MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 4)), 400) = 0
OR
(
MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 4)), 100) <> 0
AND
MOD (TO_NUMBER (SUBSTRB (p_idcard, 7, 4)), 4) = 0
)
THEN -- 闰年
v_regstr :=
'^[1-9][0-9]{5}(19|20)[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|[1-2][0-9]))[0-9]{3}[0-9Xx]$';
ELSE
v_regstr :=
'^[1-9][0-9]{5}(19|20)[0-9]{2}((01|03|05|07|08|10|12)(0[1-9]|[1-2][0-9]|3[0-1])|(04|06|09|11)(0[1-9]|[1-2][0-9]|30)|02(0[1-9]|1[0-9]|2[0-8]))[0-9]{3}[0-9Xx]$';
END IF;
IF REGEXP_LIKE (p_idcard, v_regstr) THEN
v_sum :=
( TO_NUMBER (SUBSTRB (p_idcard, 1, 1))
TO_NUMBER (SUBSTRB (p_idcard, 11, 1))
)
* 7
( TO_NUMBER (SUBSTRB (p_idcard, 2, 1))
TO_NUMBER (SUBSTRB (p_idcard, 12, 1))
)
* 9
( TO_NUMBER (SUBSTRB (p_idcard, 3, 1))
TO_NUMBER (SUBSTRB (p_idcard, 13, 1))
)
* 10
( TO_NUMBER (SUBSTRB (p_idcard, 4, 1))
TO_NUMBER (SUBSTRB (p_idcard, 14, 1))
)
* 5
( TO_NUMBER (SUBSTRB (p_idcard, 5, 1))
TO_NUMBER (SUBSTRB (p_idcard, 15, 1))
)
* 8
( TO_NUMBER (SUBSTRB (p_idcard, 6, 1))
TO_NUMBER (SUBSTRB (p_idcard, 16, 1))
)
* 4
( TO_NUMBER (SUBSTRB (p_idcard, 7, 1))
TO_NUMBER (SUBSTRB (p_idcard, 17, 1))
)
* 2
TO_NUMBER (SUBSTRB (p_idcard, 8, 1)) * 1
TO_NUMBER (SUBSTRB (p_idcard, 9, 1)) * 6
TO_NUMBER (SUBSTRB (p_idcard, 10, 1)) * 3;
v_mod := MOD (v_sum, 11);
v_checkbit := SUBSTRB (v_checkcode, v_mod 1, 1);
IF v_checkbit = upper(substrb(p_idcard,18,1)) THEN
RETURN 1;
ELSE
RETURN 0;
END IF;
ELSE
RETURN 0;
END IF;
ELSE
RETURN 0; -- 身份证号码位数不对
END CASE;
EXCEPTION
WHEN OTHERS
THEN
RETURN 0;
END fn_checkidcard;
/
Show Err;
觉得有用的朋友多帮忙转发哦！后面会分享更多devops和DBA方面的内容，感兴趣的朋友可以关注下~
